cwitts at gmail.com
Tue Aug 5 14:58:59 CEST 2008
On Aug 5, 2:23 pm, Jeff <jeffo... at gmail.com> wrote:
> On Aug 5, 7:10 am, Marc 'BlackJack' Rintsch <bj_... at gmx.net> wrote:
> > On Tue, 05 Aug 2008 11:39:36 +0100, Fred Mangusta wrote:
> > > In other words I'd like to replace all the instances of a '.' character
> > > with something (say nothing at all) when the '.' is representing a
> > > decimal separator. E.g.
> > > 500.675 ----> 500675
> > > but also
> > > 1.000.456.344 ----> 1000456344
> > > I don't care about the fact the the resulting number is difficult to
> > > read: as long as it remains a series of digits it's ok: the important
> > > thing is to get rid of the period, because I want to keep it only where
> > > it marks the end of a sentence.
> > > I was trying to do like this
> > > s=re.sub("[(\d+)(\.)(\d+)]","... ",s)
> > > but I don't know much about regular expressions, and don't know how to
> > > get the two groups of numbers and join them in the sub. Moreover doing
> > > like this I only match things like "345.000" and not "1.000.000".
> > > What's the correct approach?
> > In : re.sub(r'(\d)\.(\d)', r'\1\2', '1.000.456.344')
> > Out: '1000456344'
> > Ciao,
> > Marc 'BlackJack' Rintsch
> Even faster:
> '1.000.456.344'.replace('.', '') => '1000456344'
Doesn't work for his use case as he wants to keep periods marking the
end of a sentence.
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