find and replace with regular expressions

[dusans]

On Jul 31, 10:07 pm, chrispoliq... at gmail.com wrote:
> I am using regular expressions to search a string (always full
> sentences, maybe more than one sentence) for common abbreviations and
> remove the periods.  I need to break the string into different
> sentences but split('.') doesn't solve the whole problem because of
> possible periods in the middle of a sentence.
>
> So I have...
>
> ----------------
>
> import re
>
> middle_abbr = re.compile('[A-Za-z0-9]\.[A-Za-z0-9]\.')
>
> # this will find abbreviations like e.g. or i.e. in the middle of a
> sentence.
> # then I want to remove the periods.
>
> ----------------
>
> I want to keep the ie or eg but just take out the periods.  Any
> ideas?  Of course newString = middle_abbr.sub('',txt) where txt is the
> string will take out the entire abbreviation with the alphanumeric
> characters included.

Its impossible with regex. U could try it with a statistical analysis;
and even this would give u a good split.