regex question

Jeff jeffober at gmail.com
Tue Aug 5 14:23:19 CEST 2008


On Aug 5, 7:10 am, Marc 'BlackJack' Rintsch <bj_... at gmx.net> wrote:
> On Tue, 05 Aug 2008 11:39:36 +0100, Fred Mangusta wrote:
> > In other words I'd like to replace all the instances of a '.' character
> > with something (say nothing at all) when the '.' is representing a
> > decimal separator. E.g.
>
> > 500.675  ---->       500675
>
> > but also
>
> > 1.000.456.344 ----> 1000456344
>
> > I don't care about the fact the the resulting number is difficult to
> > read: as long as it remains a series of digits it's ok: the important
> > thing is to get rid of the period, because I want to keep it only where
> > it marks the end of a sentence.
>
> > I was trying to do like this
>
> > s=re.sub("[(\d+)(\.)(\d+)]","... ",s)
>
> > but I don't know much about regular expressions, and don't know how to
> > get the two groups of numbers and join them in the sub. Moreover doing
> > like this I only match things like "345.000" and not "1.000.000".
>
> > What's the correct approach?
>
> In [13]: re.sub(r'(\d)\.(\d)', r'\1\2', '1.000.456.344')
> Out[13]: '1000456344'
>
> Ciao,
>         Marc 'BlackJack' Rintsch

Even faster:

'1.000.456.344'.replace('.', '') => '1000456344'



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