urldecode function?

Edwin.Madari at VerizonWireless.com Edwin.Madari at VerizonWireless.com
Thu Aug 14 23:17:54 CEST 2008


afraid not.. simple to create your own, NOTE that key words can be supplied more than once. Hence... 
============================================
import urllib
 
def urldecode(query):
   d = {}
   a = query.split('&')
   for s in a:
      if s.find('='):
         k,v = map(urllib.unquote, s.split('='))
         try:
            d[k].append(v)
         except KeyError:
            d[k] = [v]
 
   return d
 
s = 'Cat=1&by=down&start=1827&start=1234&anotherCat=me%3Dow%7e'
print urldecode(s)
====================================================
prints out following and preserves the order of inputs for those keys given more than once as with 'start' key
{'start': ['1827', '1234'], 'anotherCat': ['me=ow~'], 'by': ['down'], 'Cat': ['1']}
 
 
hope that helps..
Edwin
 

-----Original Message-----
From: python-list-bounces+edwin.madari=verizonwireless.com at python.org [mailto:python-list-bounces+edwin.madari=verizonwireless.com at python.org]On Behalf Of rkmr.em at gmail.com
Sent: Thursday, August 14, 2008 12:32 PM
To: python-list at python.org
Subject: urldecode function?


hi
is there a function that does the opposite of urllib.urlencode? 

for example
urldecode('Cat=1&by=down&start=1827')

returns a dictionary with {'Cat':1, 'by':'down','start':1827)

thanks




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