Problem with list.insert

[Diez B. Roggisch]

SUBHABRATA schrieb:
> Some people in the room told I am kidding, but I learnt Python from
> Python docs which gives examples like these,
> But I write explicit comments,
> an excerpt from python docs:
> # Measure some strings:
> ... a = ['cat', 'window', 'defenestrate']
>>>> for x in a:
> ...     print x, len(x)
> ...
> cat 3
> window 6
> defenestrate 12
> But well, if you are suggesting improvement I'll surely listen.

Please! Just because a tiny 3 lines example involing just *one* list 
doesn't give that a long & speaking name does not mean

> The outputs are given in Hindi, it is a dictionary look up program,
> the matching words are in Hindi, you may leave aside them.
> How to debug the result string is to see the words which are in
> English as the group page does not take italics so I am putting one
> asterisk* after it
> NO PROBLEM:
> INPUT:
> he has come
> OUTPUT IS
> उओह/ उन्होने रहेसाक्ता २.यात्राकरना
> PROBLEM:
> INPUT:
> (i) Lincoln* has come
> OUTPUT IS:
> रहेसाक्ता २.यात्राकरना lincoln*
> lincoln lincoln* रहेसाक्ता २.यात्राकरना lincoln
> lincoln lincoln* lincoln* रहेसाक्ता २.यात्राकरना lincoln
> ….and increasing the number and seems a never ending process.
> MY EXPEPECTED STRING IS:
> lincoln रहेसाक्ता २.यात्राकरना lincoln^
> The latter places marked^ I am editing don't worry for that,
> though MY FINAL EXPECTED STRING IS:
> lincoln रहेसाक्ता २.यात्राकरना
> Best Regards,
> Subhabrata.
> 
> 
> 
> Marc 'BlackJack' Rintsch wrote:
>> On Thu, 28 Aug 2008 09:13:00 -0700, SUBHABRATA wrote:
>>
>>> import re
>>> def wordchecker1(n):
>>>     # INPUTTING STRING
>>>     a1=raw_input("PRINT ONE ENGLISH SENTENCE FOR DICTIONARY CHECK:")
>>>     #CONVERTING TO LOWER CASE
>>>     a2=a1.lower()
>>>     #CONVERTING INTO LIST
>>>     a3=a2.split()
>>>     #DICTIONARY
>>>     a4=open("/python25/Changedict3.txt","r") a5=a4.read()
>>>     a6=a5.split()
>>>     found=[]
>>>     not_found=[]
>>>    #SEARCHING DICTIONARY
>>>     for x in a3:
>>>         a7="\n"
>>>         a8=a7+x
>>>         if a8 in a5:
>>>             a9=a5.index(a8)
>>>             a10=a5[a9:]
>>>             a11=re.search("\xe0.*?\n",a10)
>>>             a12=a11.group()
>>>             a13=a12[:-1]
>>>             found.append(a13)
>>>         elif a8 not in a5:
>>>             a14=x
>>>             not_found.append(a14)
>>>         else:
>>>             print "Error"
>>>     found.extend(not_found)
>>>     # THE OUTPUT
>>>     print "OUTPUT STRING IS"
>>>     a15=(' '.join(found))
>>>     #THE OUTPUT STRING
>>>     print a15
>>>     # SPLITTING OUTPUT STRING IN WORDS
>>>     a16=a15.split()
>>>     #TAKING OUT THE WORD FROM OUTPUT STRING for word in a16:
>>>         #MATCHING WITH GIVEN STRING
>>>         a17=a2.find(word)
>>>         if a17>-1:
>>>             print "The word is found in the Source String"
>>>             a18=a3.index(word)
>>>             a19=a3[a18]
>>>             print a19
>>>             #INSERTING IN THE LIST OF TARGET STRING
>>>             a20=a16.insert(a18,a19)
>>>             print a16
>>>             a21=(" ".join(a16))
>>>             print a21
>> a1, a2, a2, …, a20?  You must be kidding.  Please stop numbering names
>> and use *meaningful* names instead!
>>
>> Could you describe them problem better, with sample inputs and expected
>> outputs.  There must be a better way that that unreadable mess above.
>>
>> Ciao,
>> 	Marc 'BlackJack' Rintsch