Weird expression result

[Dan Lenski]

On Mon, 18 Aug 2008 18:04:32 +0200, Peter Otten wrote:
> This works just like a < b < c:
> 
>>>> 3 in [3] and [3] == True
> False
> 
> Peter

Interesting.  I agree with the OP that it is confusing!

Does this expansion really get invoked every time there is an expression 
of the form??

expr1 binary_op1 expr2 binary_op2 expr3 ...

Seemingly, the answer is yes:

 >>> 3 in [3] in [[3],[4]] in [[[3],[4]],5] == [[[3],[2+2]],5]
 True

How does this play with standard precedence rules?

Dan