Return a string result with out breaking loop

[Andrew]

Hi Ive been trying with yield all day and other different things :D

but I always get the same result using yield

Fault: <Fault 1: "<type 'exceptions.TypeError'>:cannot marshal <type 
'generator'
 > objects">

I'm not sure exactly what I am doing wrong as this is the first time Ive 
used yield

Any suggestions on how to fix this error

Cheers

Andrew


Christian Heimes wrote:
> Andrew wrote:
>> Hi I was wondering if there is anyway with XML RPC to send a string of 
>> text from the server to the client with out calling return thus 
>> breaking  my loop
>>
>> for example
>>
>>  def somefunc():
>>       for action, files in results:
>>               full_filename = os.path.join(path_to_watch, files)
>>               theact = ACTIONS.get(action, "Unknown")
>>               out2 =  str(full_filename) +  " " + str(theact)
>>               return out2
>>
>> the return statement will return a result breaking my loop. My goal is 
>> to have it continue looping and updating the client
>>
>> any ideas?
> 
> Yes, use yield instead of return. It turns the function into a generator.
> 
> Christian
>