Weird expression result

[Peter Otten]

Dan Lenski wrote:

> On Mon, 18 Aug 2008 18:04:32 +0200, Peter Otten wrote:
>> This works just like a < b < c:
>> 
>>>>> 3 in [3] and [3] == True
>> False

> Interesting.  I agree with the OP that it is confusing!
> 
> Does this expansion really get invoked every time there is an expression
> of the form??
> 
> expr1 binary_op1 expr2 binary_op2 expr3 ...
> 
> Seemingly, the answer is yes:
> 
>  >>> 3 in [3] in [[3],[4]] in [[[3],[4]],5] == [[[3],[2+2]],5]
>  True
> 
> How does this play with standard precedence rules?

Simple, all comparisons have the same priority:

http://docs.python.org/ref/comparisons.html

Peter