file data to list

[Sion Arrowsmith]

Emile van Sebille  <emile at fenx.com> wrote:
>data = zip(*[xx.split() for xx in open('data.txt').read().split("\n")])

Files are iterable:

data = zip(*[xx.rstrip().split() for xx in open('data.txt')])

saves you creating the extra intermediate list resulting from split("\n").

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