Lining Up and PaddingTwo Similar Lists

[Boris Borcic]

D,T=[dict((x.split('.')[0],x) for x in X) for X in (dat,txt)]
for k in sorted(set(D).union(T)) :
     for S in D,T :
         print '%-8s' % S.get(k,'None'),
     print

HTH

W. eWatson wrote:
> Maybe there's some function like zip or map that does this. If not, it's 
> probably fairly easy to do with push and pop. I'm just checking to see 
> if there's not some known simple single function that does what I want. 
> Here's what I'm trying to do.
> 
> I have a list dat like (assume the items are strings even thought I'm 
> omitting quotes.):
> [a.dat, c.dat, g.dat, k.dat, p.dat]
> 
> I have another list called txt that looks like:
> [a.txt, b.txt, g.txt, k.txt r.txt, w.txt]
> 
> What I need is to pair up items with the same prefix and use "None", or 
> some marker, to indicate the absence of the opposite item. That is, in 
> non-list form, I want:
> a.dat a.txt
> None  b.txt
> c.dat None
> g.dat g.txt
> k.dat k.txt
> p.dat  None
> None  r.txt
> None  w.txt
> 
> Ultimately, what I'm doing is to find the missing member of pairs.