How to manipulate list of dictionary
Bruno Desthuilliers
bruno.42.desthuilliers at websiteburo.invalid
Tue Aug 26 05:25:03 EDT 2008
Simon Brunning a écrit :
> 2008/8/26 ajak_yahoo <arazak73 at yahoo.com.my>:
>> Need some help, I have a list of dictionary as below,
>>
>> table = [{"Part #":"Washer","Po #":"AE00128","qty":100},
>> {"Part #":"Brake Pad","Po #":"AE00154","qty":150},
>> {"Part #":"Mesh","Po #":"AE00025","qty":320},
>> {"Part #":"Mouse","Po #":"AE00207","qty":120},
>> {"Part #":"Insulator","Po #":"AE0013","qty":190}]
>>
>> How to manipulate the table?
>>
>> I need to search for the Po #, and display the result as below.
>>
>>
>> Part # : Mouse
>> Po # : AE00207
>> Qty : 120 pcs
>
> Well, that's a really bad data structure for what you want to do, but
> you can do it with something like (untested):
>
> wanted = 'AE00207'
>
> for part in table:
> if part['Po #'] == wanted:
> print "Part #:\t%(Part #)s\nPo #:\t%(Po #)s\nQty #:\t%(qty)s" % part
>
Which will not be very efficient if you happen to have lot of items in
your list and or a lot of searches to do.
The next solution is to maintain an index, ie:
def make_index(table, key):
index = {}
for record in enumerate(table):
index.setdefault(record[key], []).append(record)
return index
po_index = make_index(table, "Po #")
results = po_index.get('AE00207', None)
But this won't scale up if you have millions of records. So the next
next solution is to use a true database - either a RDBMS, or an embedded
one like SQLite.
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