Strange return behavior for function

[Robert Dailey]

On Tue, Aug 5, 2008 at 10:05 AM, Robert Dailey <rcdailey at gmail.com> wrote:

> Hi,
>
> I've created a function to normalize Subversion URLs, however when I return
> a string, printing the result of the function becomes "None". When I print
> the value of the string before I return from the function, I see a valid
> string. What's going on? The function is below:
>
>
> def normurl( url_root, url ):
>     mutableurl = url[len(url_root):]
>
>     split1 = mutableurl.split( "..", 1 )
>     if len(split1) == 1:
>         print "Returning:", split1[0]
>         return split1[0]
>
>     split2 = split1[0][:-1].rsplit( "/", 1 )
>     combined = split2[0] + split1[1]
>     normurl( url_root, url_root + combined )
>

Bah, never mind. I just figured it out. I needed a 'return' before my
recursive normurl() call. Sorry for the wasted post!
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