CONNECTION TIMED OUT ERROR using urllib2

rishi pathak mailmaverick666 at gmail.com
Fri Dec 5 07:27:22 CET 2008


Are you sitting behind a proxy. If so then you have to set proxy for http

On Fri, Dec 5, 2008 at 11:47 AM, svalbard colaco
<svalbardcolaco at gmail.com>wrote:

> Hi all
>
> I have written a small code snippet to open a URL using urllib2 to open a
> web page , my python version is 2.4 but i get an urlopen error called
> connection timed out
>
> The following is the code snippet
>
> *import urllib2
>
> f = urllib2.urlopen('http://www.google.com/')
> print f.read(100)*
>
>
> where as the same url http://www.google.com/ works through my browser.
>
> The following is the back trace :
>
> File "test_url.py", line 3, in ?
>     f = urllib2.urlopen('http://www.google.com/')
>   File "/usr/lib/python2.4/urllib2.py", line 130, in urlopen
>     return _opener.open(url, data)
>   File "/usr/lib/python2.4/urllib2.py", line 358, in open
>     response = self._open(req, data)
>   File "/usr/lib/python2.4/urllib2.py", line 376, in _open
>     '_open', req)
>   File "/usr/lib/python2.4/urllib2.py", line 337, in _call_chain
>     result = func(*args)
>   File "/usr/lib/python2.4/urllib2.py", line 1021, in http_open
>     return self.do_open(httplib.HTTPConnection, req)
>   File "/usr/lib/python2.4/urllib2.py", line 996, in do_open
>     raise URLError(err)
> *urllib2.URLError: <urlopen error (110, 'Connection timed out*')>
>
>
> Any pointers in this regard will be of great help.
>
> Thanking you'll in advance.
>
> Regards,
> sv
>
>
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>


-- 
Regards--
Rishi Pathak
Pune-Maharastra
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