regex problem ..

Analog Kid garlictrompet at gmail.com
Wed Dec 17 12:03:24 CET 2008


Hi guys:
Thanks for your responses. Points taken. Basically, I am looking for a
combination of the following ...
[^\w] and %(?!20) ... How do I do this in a single RE?

Thanks for all you help.
Regards,
AK

On Mon, Dec 15, 2008 at 10:54 PM, Steve Holden <steve at holdenweb.com> wrote:

> Analog Kid wrote:
> > Hi All:
> > I am new to regular expressions in general, and not just re in python.
> > So, apologies if you find my question stupid :) I need some help with
> > forming a regex. Here is my scenario ...
> > I have strings coming in from a list, each of which I want to check
> > against a regular expression and see whether or not it "qualifies". By
> > that I mean I have a certain set of characters that are permissible and
> > if the string has characters which are not permissible, I need to flag
> > that string ... here is a snip ...
> >
> > flagged = list()
> > strs = ['HELLO', 'Hi%20There', '123123@#@']
> > p =  re.compile(r"""[^a-zA-Z0-9]""", re.UNICODE)
> > for s in strs:
> >     if len(p.findall(s)) > 0:
> >         flagged.append(s)
> >
> > print flagged
> >
> > my question is ... if I wanted to allow '%20' but not '%', how would my
> > current regex (r"""[^a-zA-Z0-9]""") be modified?
> >
> The essence of the approach is to observe that each element is a
> sequence of zero or more "character", where character is "either
> letter/digit or escape." So you would use a pattern like
>
> "([a-zA-Z0-9]|%[0-9a-f][0-9a-f])+"
>
>
> regards
>  Steve
> --
> Steve Holden        +1 571 484 6266   +1 800 494 3119
> Holden Web LLC              http://www.holdenweb.com/
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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