why cannot assign to function call

[Erik Max Francis]

scsoce wrote:

> I have a function return a reference, and want to assign to the 
> reference, simply like this:
>  >>def f(a)
>          return a
>     b = 0
>    * f( b ) = 1*
> but the last line will be refused as "can't assign to function call".
> In my thought , the assignment is very nature,  but  why the interpreter 
> refused to do that ?

Because, as in most languages, it's not even clear what you might mean 
by this syntax.  It doesn't have any meaning; assignments are made to 
variables, not the results of function calls.

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