How to identify which numbers in a list are within each others' range
Matthew_WARREN at bnpparibas.com
Matthew_WARREN at bnpparibas.com
Fri Feb 1 07:54:27 EST 2008
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attn.steven.kuo at gmail.com
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Re: How to identify which numbers in a list are within each others'
31/01/2008 22:48 range
On Jan 31, 8:12 am, erikcw <erikwickst... at gmail.com> wrote:
> Hi,
>
> I have a list of numbers each with a +/- margin of error. I need to
> identify which ones overlab each other.
>
> For example:
> 55 +/- 3
> 20 +/- 2
> 17 +/- 4
> 60 +/- 3
>
> #base, max, min
> list = [
> (55, 58, 52),
> (20, 22, 18),
> (17, 21, 13),
> (60, 63, 57),
> ]
>
> In this example the range of list[0] overlaps the range of list[3] AND
> list[1] overlaps list[2]
>
> What is the best way to in python to identify the list items that
> overlap and the items that don't overlap with any other.
>
Is this usable?
Assuming you transform your 3 tuples into a list of start-end 2 tuples and
sort them for lowest to highest, then
lst=[(55,58,52),(20,22,18),(17,21,13),(60,63,57)]
a=[ (l[2],l[1]) for l in lst ]
a.sort()
a=[(1,5),(4,9),(10,12),(11,15),(16,19)]
i=[ (pair,a[a.index(pair)+1]) for pair in a[:-1] if
a[a.index(pair)+1][0]<pair[1]]
i
[((13, 21), (18, 22)), ((52, 58), (57, 63))]
?
Matt.
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