Making string-formatting smarter by handling generators?
grflanagan at gmail.com
grflanagan at gmail.com
Wed Feb 27 11:58:05 EST 2008
On Feb 27, 5:23 pm, Tim Chase <python.l... at tim.thechases.com> wrote:
> Is there an easy way to make string-formatting smart enough to
> gracefully handle iterators/generators? E.g.
>
> transform = lambda s: s.upper()
> pair = ('hello', 'world')
> print "%s, %s" % pair # works
> print "%s, %s" % map(transform, pair) # fails
>
> with a """
> TypeError: not enough arguments for format string
> """
>
> I can force it by wrapping the results of my generator in a call
> to tuple() or list()
>
> print "%s, %s" % tuple(map(transform, pair))
>
> but it feels a bit hackish to me.
>
> I find I hit it mostly with calls to map() where I want to apply
> some transform (as above) to all the items in a list of
> parameters such as
>
> "%s=%s&%s=%s" % map(urllib.quote, params)
>
> Any suggestions? (even if it's just "get over your hangup with
> wrapping the results in list()/tuple()" :)
>
> Thanks,
>
> -tkc
FWIW, I had a similar problem and came up with a custom scheme:
http://gflanagan.net/site/python/utils/template.py
(still a work in progress).
>From the doctest:
Map operator. Expects a list (iterator) whose each item is either a
tuple
or a dict. If the variable exists (and optionally is not null), then
for each tuple/dict yield the formatted default.
>>> t = Template("""
... {{names|
... Hello %s %s!
... }}
... """)
>>> print t.replace()
Traceback (most recent call last):
...
KeyError: 'names'
>>> print t.replace(names=[('John', 'Doe'), ('Jane', 'Doe')])
Hello John Doe!
Hello Jane Doe!
HTH
Gerard
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