When is min(a, b) != min(b, a)?
marduk at python.invalid
Mon Jan 21 04:15:02 CET 2008
This issue may have been referred to in
news:<mailman.1864.1196703799.13605.python-list at python.org> but I didn't
entirely understand the explanation. Basically I have this:
>>> a = float(6)
>>> b = float('nan')
>>> min(a, b)
>>> min(b, a)
>>> max(a, b)
>>> max(b, a)
Before I did not know what to expect, but I certainly didn't expect
this. So my question is what is the min/max of a number and NaN or is it
not defined (for which I would have expected either an exception to be
raised or NaN returned in each case).
As a corrollary would I be able to rely on the above behavior or is it
subject to change (to fix a bug in min/max perhaps :-)?
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