next line (data parsing)

George Sakkis george.sakkis at gmail.com
Thu Jan 17 06:50:44 CET 2008


On Jan 17, 12:42 am, George Sakkis <george.sak... at gmail.com> wrote:
> On Jan 17, 12:01 am, Scott David Daniels <Scott.Dani... at Acm.Org>
> wrote:
>
>
>
> > robleac... at gmail.com wrote:
> > > Hi there,
> > > I'm struggling to find a sensible way to process a large chuck of
> > > data--line by line, but also having the ability to move to subsequent
> > > 'next' lines within a for loop. I was hoping someone would be willing
> > > to share some insights to help point me in the right direction. This
> > > is not a file, so any file modules or methods available for files
> > > parsing wouldn't apply.
>
> > > I can iterate over each line by setting a for loop on the data object;
> > > no problem. But basically my intension is to locate the line "Schedule
> > > HOST" and progressively move on to the 'next' line, parsing out the
> > > pieces I care about, until I then hit "Total", then I resume to the
> > > start of the for loop which locates the next "Schedule HOST".
>
> > if you can do:
>
> >      for line in whatever:
> >          ...
>
> > then you can do:
>
> >      source = iter(whatever)
> >      for intro in source:
> >          if intro.startswith('Schedule '):
> >              for line in source:
> >                  if line.startswith('Total'):
> >                      break
> >                  process(intro, line)
>
> > --Scott David Daniels
> > Scott.Dani... at Acm.Org
>
> Or if you use this pattern often, you may extract it to a general
> grouping function such ashttp://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/521877:

Sorry, google groups fscked up with the auto linewrapping (is there a
way to increase the line length?); here it is again:

import re

for line in iterblocks(source,
        start = lambda line: line.startswith('Schedule HOST'),
        end = lambda line: re.search(r'^\s*Total',line),
        skip_delim = False):
    process(line)


George



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