When is min(a, b) != min(b, a)?
grante at visi.com
Mon Jan 21 17:15:02 CET 2008
On 2008-01-21, Albert Hopkins <marduk at python.invalid> wrote:
> This issue may have been referred to in
> news:<mailman.1864.1196703799.13605.python-list at python.org> but I didn't
> entirely understand the explanation. Basically I have this:
> >>> a = float(6)
> >>> b = float('nan')
> >>> min(a, b)
> >>> min(b, a)
> >>> max(a, b)
> >>> max(b, a)
> Before I did not know what to expect, but I certainly didn't expect
> this. So my question is what is the min/max of a number and NaN or is it
> not defined (for which I would have expected either an exception to be
> raised or NaN returned in each case).
For applications I work on, it should be NaN. But I think the
result of comparing a Normal to a NaN is undefined, so the
above behavior is allowed by the IEEE spec.
> As a corrollary would I be able to rely on the above behavior or is it
> subject to change (to fix a bug in min/max perhaps :-)?
According to Wikipedia:
In the proposed IEEE 754r revision of that standard the same
rule applies, except that a few anomalous functions (such as
the maxnum function, which returns the maximum of two
operands which are expected to be numbers) favour numbers --
if just one of the operands is a NaN then the value of the
other operand is returned.
A different approach has been implemented in the NaN
'toolbox' for GNU Octave and MATLAB. In that toolbox, NaNs
are assumed to represent missing values and so the
statistical functions ignore NaNs in the data instead of
propagating them. Every computation in the NaN toolbox is
based on the data values only, which can be useful if it is
known that NaNs cannot be produced by errors.
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