# seemingly simple list indexing problem

iu2 israelu at elbit.co.il
Tue Jul 29 08:41:51 CEST 2008

```On Jul 29, 3:59 am, John Machin <sjmac... at lexicon.net> wrote:
> On Jul 29, 8:10 am, John Krukoff <jkruk... at ltgc.com> wrote:
>
>
>
>
>
> > On Mon, 2008-07-28 at 16:24 -0500, Ervan Ensis wrote:
> > > My programming skills are pretty rusty and I'm just learning Python so
> > > this problem is giving me trouble.
>
> > > I have a list like [108, 58, 68].  I want to return the sorted indices
> > > of these items in the same order as the original list.  So I should
> > > return [2, 0, 1]
>
> > > For a list that's already in order, I'll just return the indices, i.e.
> > > [56, 66, 76] should return [0, 1, 2]
>
> > > Any help would be appreciated.
>
> > > --
> > >http://mail.python.org/mailman/listinfo/python-list
>
> > If your lists aren't so large that memory is an issue, this might be a
> > good place for a variation of decorate, sort, undecorate.
>
> > >>> listToSort = [ 108, 58, 68 ]
> > >>> decorated = [ ( data, index ) for index, data in
>
> > enumerate( listToSort ) ]>>> decorated
>
> > [(108, 0), (58, 1), (68, 2)]>>> result = [ None, ] * len( listToSort )
> > >>> for sortedIndex, ( ignoredValue, originalIndex ) in
>
> > enumerate( sorted( decorated ) ):
> > ...     result[ originalIndex ] = sortedIndex
> > ...>>> result
>
> > [2, 0, 1]
>
> Simpliciter:
>
>
>
> >>> data = [99, 88, 77, 88, 66]
> >>> [x[1] for x in sorted(zip(data, xrange(len(data))))]
> [4, 2, 1, 3, 0]
>
> Use case? Think data == database table, result == index ...- Hide quoted text -
>
> - Show quoted text -

I think it is wrong, using this on my data returns the wrong result
data = [108, 58, 68, 108]
>>> [x[1] for x in sorted(zip(data, xrange(len(data))))]
[1, 2, 0, 3]

```