storing references instead of copies in a dictionary

mk mrkafk at gmail.com
Thu Jul 17 17:05:57 CEST 2008


> def f2(arg):
>     return "f2 "+arg
> 
> def f1(arg):
>     return "f1 "+arg
> 
> a={"1":"f1","2":"f2"}
> print [eval(x[1])(x[0]) for x in a.items()]
> def f2(arg):
>     return "New f2 "+arg
> print [eval(x[1])(x[0]) for x in a.items()]

Neat trick, if probably dangerous in some circumstances. Anyway, thanks, 
I didn't think of that.

> Don't know if this is any use to you..

At least I learned something. :-)







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