simple UnZip

noydb jenn.duerr at gmail.com
Wed Jul 2 15:39:51 CEST 2008


Can someone help me with this script, which I found posted elsewhere?
I'm trying to figure out what is going on here so that I can alter it
for my needs, but the lack of descriptive names is making it
difficult.  And, the script doesn't quite do anything worthwhile -- it
unzips one file from a zipfile, not all files in a zipfile.

***
import zipfile, os, sys, glob

os.chdir("C:\\Temp")
zips = glob.glob('*.zip')

for fzip in zips:
    if zipfile.is_zipfile(fzip):
        print fzip," is a zip"
        z = zipfile.ZipFile(fzip,'r')
        lstName = z.namelist()
        sHgt = lstName[0]
        print "Unpacking",sHgt
        hgt = z.read(sHgt)
        fHgt = open(sHgt,'wb')
        fHgt.write(hgt)
        # fHgt.flush
        fHgt.close
print "Finished"
***

I changed it somewhat to
&&&
import zipfile, os, sys

event_zip = ("C:\\Temp\\data4event.zip")

z = zipfile.ZipFile(event_zip, 'r')

zList = z.namelist()

for zItem in zList:
    print "Unpacking",zItem
    zRead = z.read(zItem)
    z1File = open(zItem,'wb')
    z1File.write(zRead)
    z1File.close
print "Finished"
&&&

This works, but I want to be able to specify a different output
location.

The scenario is that the zip file will always be the same (gets copied
over daily), but it needs to be unzipped to a specific different
directory.

Can anyone help?

Thanks!



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