Question on Joining of list

[Quentin Gallet-Gilles]

Actually, since you want to keep the missing words apart from the found
ones, it's not necessary to do that. Using "first_char" and "missing_word"
(quoting Peter's code) as lists instead of strings comes to mind, then you
can join both lists into a string once the code exits the for loop.

Cheers,
Quentin

On Fri, Jul 18, 2008 at 12:34 PM, Subhabrata Banerjee <
subhabrata.iisc at hotmail.com> wrote:

>  Dear Quentin,
> That's true but where to place, if I use it after elif it is not giving
> result but if I give in after for there is no use of iteration.
> I'm thinking to use a3.find(s) whichever not availiable to split and
> iterate and join with s.
> Best Regards,
> Subhabrata.
>
>
> ------------------------------
>
> Date: Fri, 18 Jul 2008 12:11:00 +0200
> From: qgallet at gmail.com
> To: subhabrata.iisc at hotmail.com
> Subject: Re: Question on Joining of list
>
>
>
> In that case, the line 's=a5+" "+a6' should be inside the for loop (and
> slightly modified to concatenate the results)
>
> Cheers,
> Quentin
>
> On Fri, Jul 18, 2008 at 12:00 PM, SUBHABRATA <subhabrata.iisc at hotmail.com>
> wrote:
>
> Sorry if I didn't say that.
> The input is a string "Petrol Helium Heaven Sky"
> Now, in a3 it is "God Goddess Heaven Sky" is there,
> it is matching Heaven and Sky but not Petrol and Helium as they are
> not in a3.
> Now, as per the code it is giving me an output "S" of "Sky" and
> "Helium"
> But I was looking for an output of  "H S Petrol Helium" and not "S
> Helium" meaning all the values of a5 and a6 will be concatenated in s.
> Best Regards,
> Subhabrata..
>
> Marc 'BlackJack' Rintsch wrote:
> > On Fri, 18 Jul 2008 01:31:59 -0700, SUBHABRATA wrote:
> >
> > > def try2(n):
> > >     a1=raw_input("PRINT A STRING:")
> > >     a2=a1.split()
> > >     a3="God Godess Heaven Sky"
> > >     for x in a2:
> > >             a4=a3.find(x)
> > >             if a4>-1:
> > >                     a5=a3[a4]
> > >                     print a5
> > >             elif a4<0:
> > >                     a6=x
> > >                     print "It is not found"
> > >                     print a6
> > >             else:
> > >                     print "Error"
> > >     s=a5+" "+a6
> > >     print s
> > >
> > > Here, if I put a string like:
> > > Petrol Helium Heaven Sky
> > > In s it is giving me S Helium
> > > But I am looking for an output of  a5 and a6 concatenating all its
> > > values not the last ones. Can you suggest me any help? Am I missing
> > > any minor point?
> >
> > Maybe you should describe what the input looks like and what output you
> > want to have and how the input and output are connected.  In words, not
> in
> > not very clear code with "numbered names".  That's a silly idea and makes
> > understanding the code very hard.  Please use meaningful names!
> >
> > Ciao,
> >       Marc 'BlackJack' Rintsch
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
>
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