creating yaml without tags using pyyaml

Stephen Moore delfick755 at gmail.com
Fri Jun 6 13:19:56 CEST 2008


hello

I have a situation where I have quite a large python object which I
want to convert to yaml so I can then send it to a flex application
using pyamf.

I've managed to create a yaml document using the python object
(http://flashbsm.googlecode.com/svn/testing/yamlTest/tester.yaml)
(using pyyaml)

however when I send the result of decoding the python object to yaml
to the flex app, the flex app complains about expecting a block end,
but not getting one.

I have come to the conclusion that this is the fault of the tags (for
example, !!python/tuple) as getting rid of them gets rid of the
errors.

So I'm wondering if there is an option to YAML.decode that will create
a yaml document without the tags?

Thankyou

Regards
Stephen



More information about the Python-list mailing list