Simple regular expression
srhegde at gmail.com
Fri Jun 27 18:26:46 CEST 2008
On Jun 27, 11:05 am, "John Salerno" <johnj... at NOSPAMgmail.com> wrote:
> "python_enthu" <srhe... at gmail.com> wrote in message
> news:47031cc4-2b5e-43b3-9338-cf4a7b4c1568 at d45g2000hsc.googlegroups.com...
> >I am trying this.. what is wrong in this..
> > IDLE 1.2.2
> >>>> import re
> >>>> a="my name is fname lname"
> >>>> p=re.compile('name')
> >>>> m=p.match (a)
> >>>> print p.match(a)
> > None
> match( string[, pos[, endpos]])
> If zero or more characters at the beginning of string match this regular
> expression, return a corresponding MatchObject instance. Return None if the
> string does not match the pattern; note that this is different from a
> zero-length match.
> search( string[, pos[, endpos]])
> Scan through string looking for a location where this regular expression
> produces a match, and return a corresponding MatchObject instance. Return
> None if no position in the string matches the pattern; note that this is
> different from finding a zero-length match at some point in the string.
Thanks John Salerno and John Machin,
I am used to perl. So I guess I am better of using re.search instead
BTW, is re.search('string') equivalent to re.match ('^string')
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