Help me on Backspace please
cakomo at gmail.com
Fri Jun 27 11:17:51 CEST 2008
On Jun 27, 11:09 am, John Machin <sjmac... at lexicon.net> wrote:
> On Jun 27, 5:27 pm, cakomo <cak... at gmail.com> wrote:
> > On Jun 27, 3:06 am, John Machin <sjmac... at lexicon.net> wrote:
> > > new_line = re.sub(r'.\x08', old_line, '')
> > > new_line = re.sub(r'[^\x08]\x08', '', old_line)
> > Thanks John
> > I will try it but, do you think regex replacement gonna erase the
> > prev. char.?
> Yair i think its gunna y do u ask?
Did i said i am a newbie still trying to figure out. But regex
statement is really what i want. Thank you very much :)
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