Programming question

Terry Reedy tjreedy at
Thu Jun 12 01:08:22 CEST 2008

"Brad Navarro" <brad.navarro at> wrote in message 
news:31C3FE622274D44A8FE8E8D649AE178805E738D4 at
Basically, what I am trying to do is get a list of each file's
attributes within a directory. Basically, the information that the 'ls
-l' command would give you in a linux shell, except the results for each
file in the directory are stored as a list.

I am presently using version 1.5 on a linux machine. I have kindly
requested my system administrator to upgrade to 2.5.2, but until then I
am afraid I am stuck with 1.5.

Our sympathies.

os.popen("ls  -l", 'r') # open a pipe to that command in read mode
Then read line by line as you would with any other file.
For append with file and info, append whatever to your list.


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