problems with opening files due to file's path

Alexnb alexnbryan at gmail.com
Tue Jun 10 20:05:04 CEST 2008


Well, now i've hit another problem, this time being that the path will be a
variable, and I can't figure out how to make startfile() make it raw with a
variable, if I put startfile(r variable), it doesn't work and
startfile(rvariable) obviously won't work, do you know how to make that work
or better yet, how to take a regular string that is given and make every
single "\" into a double "\\"?

Mike Driscoll wrote:
> 
> On Jun 10, 11:45 am, Alexnb <alexnbr... at gmail.com> wrote:
>> Gerhard Häring wrote:
>>
>> > Alexnb wrote:
>> >> Okay, so what I want my program to do it open a file, a music file in
>> >> specific, and for this we will say it is an .mp3. Well, I am using the
>> >> system() command from the os class. [...]
>>
>> >> system("\"C:\Documents and Settings\Alex\My Documents\My
>> >> Music\Rhapsody\Bryanbros\Weezer\(2001)\04 - Island In The Sun.wma\"")
>> >> [...]
>>
>> > Try os.startfile() instead. It should work better.
>>
>> > -- Gerhard
>>
>> > --
>> >http://mail.python.org/mailman/listinfo/python-list
>>
>> No, it didn't work, but it gave me some interesting feedback when I ran
>> it
>> in the shell. Heres what it told me:
>>
>> >>> os.startfile("C:\Documents and Settings\Alex\My Documents\My
>> >>> Music\Rhapsody\Bryanbros\Jason Mraz\I'm Yours (Single)\01 - I'm
>> >>> Yours.wma")
>>
>> Traceback (most recent call last):
>>   File "<pyshell#10>", line 1, in <module>
>>     os.startfile("C:\Documents and Settings\Alex\My Documents\My
>> Music\Rhapsody\Bryanbros\Jason Mraz\I'm Yours (Single)\01 - I'm
>> Yours.wma")
>>
>> WindowsError: [Error 2] The system cannot find the file specified:
>> "C:\\Documents and Settings\\Alex\\My Documents\\My
>> Music\\Rhapsody\\Bryanbros\\Jason Mraz\\I'm Yours (Single)\x01 - I'm
>> Yours.wma"
>>
>> See it made each backslash into two, and the one by the parenthesis and
>> the
>> 0 turned into an x....
>> --
>> View this message in
>> context:http://www.nabble.com/problems-with-opening-files-due-to-file%27s-pat...
>> Sent from the Python - python-list mailing list archive at Nabble.com.
> 
> Yeah. You need to either double all the backslashes or make it a raw
> string by adding an "r" to the beginning, like so:
> 
> os.startfile(r'C:\path\to\my\file')
> 
> HTH
> 
> Mike
> --
> http://mail.python.org/mailman/listinfo/python-list
> 
> 

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