any chance regular expressions are cached?

Tim Chase python.list at
Mon Mar 10 01:52:50 CET 2008

>     s=re.sub(r'\n','\n'+spaces,s)
>     s=re.sub(r'^',spaces,s)
>     s=re.sub(r' *\n','\n',s)
>     s=re.sub(r' *$','',s)
>     s=re.sub(r'\n*$','',s)
> Is there any chance that these will be cached somewhere, and save
> me the trouble of having to declare some global re's if I don't
> want to have them recompiled on each function invocation?

 >>> import this
Explicit is better than implicit

Sounds like what you want is to use the compile() call to compile 
once, and then use the resulting objects:

   re1 = re.compile(r'\n')
   re2 = re.compile(r'^')
   s = re1.sub('\n' + spaces, s)
   s = re2.sub(spaces, s)

The compile() should be done once (outside loops, possibly at a 
module level, as, in a way, they're constants) and then you can 
use the resulting object without the overhead of compiling.


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