getattr(foo, 'foobar') not the same as foo.foobar?

[Dave Kuhlman]

Arnaud Delobelle wrote:

> 
> 4.  Both points above follow from the fact that foo.bar is really a
> function call that returns a (potentially) new object: in fact what
> really happens is something like

Arnaud and Imri, too -

No.  foo.bar is *not* really a function/method call.

> 
>     Foo.__dict__['bar'].__get__(foo, Foo).
> 
> So every time foo.bar is executed an object is (or may be) created,
> with a new id.
> 
> HTH

I appreciate the help, but ...

Actually, it does not help, because ...

My understanding is that foo.bar does *not* create a new object.  All it
does is return the value of the bar attribute of object foo.  What new
object is being created?

If I have:

    class Foo(object):
        def bar(self): pass


And I do:

    foo = SomeClass()

then:

    foo.bar

should return the same (identical) object everytime, no?  yes?

I'm still confused.

- Dave

> 
> --
> Arnaud

-- 
Dave Kuhlman
http://www.rexx.com/~dkuhlman