Dominique.Holzwarth at Dominique.Holzwarth at
Thu Mar 20 16:39:50 CET 2008

Actually that's what I tried to do, for example:
outputString = myString.encode('iso-8859-1','ignore')

However, I always get such messages (the character, that's causing problems varies, but its always higher than 127 ofc...)

'ascii' codec can't decode byte 0xc3 in position 51: ordinal not in range(128) 

It doesn't matter what encoding I use (tried 'utf-8' 'utf-16' 'latin_1' and the iso one). The debugger is showing all the special characters (from french and german language) so I'm wondering why there's still the message about the 'ascii' codec...

Would that mean that the string "myString" is an ascii-string or what?

-----Original Message-----
From: Marc 'BlackJack' Rintsch [mailto:bj_666 at] 
Sent: Donnerstag, 20. März 2008 15:24
To: python-list at
Subject: Re: Problem with PARAGRAPH SEPARATOR

On Thu, 20 Mar 2008 13:03:17 +0000, Dominique.Holzwarth wrote:

> The output of the transformation (a big string containg the whole 
> file) contains a so called 'paragraph separator' (unicode: 2029). If I 
> want to pring that string (file) to the std out or a file object then 
> I get a "UnicodeError" saying that the unicode 2029 can't be encoded...
> Can anyone please tell me how I should handle that paragraph seperator?

You have to encode the unicode object in an encoding that know this character.  UTF-8 might be a candidate encoding for this.

	Marc 'BlackJack' Rintsch

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