Question on importing and function defs

[TC]

On Mar 2, 11:37 am, Gary Herron <gher... at islandtraining.com> wrote:
> TC wrote:
> > I have a problem.  Here's a simplified version of what I'm doing:
>
> > I have functions a() and b() in a module called 'mod'.  b() calls a().
>
> > So now, I have this program:
>
> > from mod import *
>
> > def a():
> >     blahblah
>
> > b()
>
> > The problem being, b() is calling the a() that's in mod, not the new
> > a() that I want to replace it.  (Both a()'s have identical function
> > headers, in case that matters.)  How can I fix this?
>
> > Thanks for any help.
>
> Since b calls mod.a, you could replace mod.a with your new a.  Like
> this:  (Warning, this could be considered bad style because it will
> confuse anyone who examines the mod module in an attempt to understand
> you code.)
>
>   import mod
>
>   def replacement_a():
>     ...
>
>   mod.a = replacement_a
>
>   ...
>
> Or another option.  Define b to take, as a parameter, the "a" function
> to call.
>
> In mod:
>
>   def a():
>    ...
>
>   def b(fn=a):  # to set the default a to call
>     ...
>
> And you main program:
>
>   from mod import *
>
>   def my_a():
>     ...
>
>   b(my_a)
>
> Hope that helps
>
> Gary Herron

Thanks for the tips, but no luck.  This is for a homework assignment,
so there are a couple of requirements, namely that I can't touch
'mod', and I have to do 'from mod import *' as opposed to 'import
mod'.

So the first method you suggested won't work as written, since the mod
namespace doesn't exist.  I tried a = replacement_a, but b() is still
calling mod's version of a() for some reason.  And because I can't
touch mod, I can't use your second suggestion.

In case I somehow oversimplified, here's the actual relevant code, in
'mod' (actually called 'search').  The first fn is what I've been
calling a(), the second is b().

(lots of stuff...)

def compare_searchers(problems, header,
searchers=[breadth_first_tree_search,
                      breadth_first_graph_search,
depth_first_graph_search,
                      iterative_deepening_search,
depth_limited_search,
                      astar_search]):
    def do(searcher, problem):
        p = InstrumentedProblem(problem)
        searcher(p)
        return p
    table = [[name(s)] + [do(s, p) for p in problems] for s in
searchers]
    print_table(table, header)

def compare_graph_searchers():
    compare_searchers(problems=[GraphProblem('A', 'B', romania),
                                GraphProblem('O', 'N', romania),
                                GraphProblem('Q', 'WA', australia)],
            header=['Searcher', 'Romania(A,B)', 'Romania(O, N)',
'Australia'])


That's the end of the 'search' file.  And here's my program, which
defines an identical compare_searchers() with an added print
statement.  That statement isn't showing up.

from search import *

def compare_searchers(problems, header,
searchers=[breadth_first_tree_search,
                      breadth_first_graph_search,
depth_first_graph_search,
                      iterative_deepening_search,
depth_limited_search,
                      astar_search, best_first_graph_search]):
    def do(searcher, problem):
        p = InstrumentedProblem(problem)
        searcher(p)
        return p
    table = [[name(s)] + [do(s, p) for p in problems] for s in
searchers]
    print 'test'
    print_table(table, header)

compare_graph_searchers()