Arbitrary precision integer arithmetic: ceiling?
amca01 at gmail.com
Sun Mar 9 00:11:53 CET 2008
I need to apply the ceiling function to arbitrary sized (long) integers.
However, division automatically returns the type of its operands, so that,
for example: math.ceil(7/4) returns 1. I can use float, as in:
math.ceil(7/float(4)), except that for very large integers float causes an
unacceptable loss of precision.
What is the best way of finding a ceiling of a quotient of arbitrary sized
More information about the Python-list