How to add function return value
George Sakkis
george.sakkis at gmail.com
Sat May 31 10:40:15 EDT 2008
On May 30, 10:16 pm, Raymond Hettinger <pyt... at rcn.com> wrote:
> On May 30, 6:21 pm, HYRY <ruoyu0... at gmail.com> wrote:
>
> > Can I write a decorator that it can automately do this conversion
>
> > def func1()
> > a = 1
>
> > --->
>
> > def func1():
> > a = 1
> > return locals()
>
> Not sure why you would want to do this, but there are several ways.
>
> 1. Make bytecode hack decorator that transforms the final "return
> None" into "return locals()". A recipe that shows the basic technique
> is at:http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/277940
>
> 2. Retrieve the source using inspect.getsourcelines(f). Then, append a
> "return locals()" to the end of the function and run it through exec.
>
> 3. Try hacking a tracing/debugging utility.
>
> 4. Run the sourcefile through tokenize, make the appropriate
> insertion, and then untokenize.
Here's an illustration of (3):
import sys
import functools
def withlocals(f):
@functools.wraps(f)
def wrapper(*args, **kwds):
f_locals = {}
def probe(frame, event, arg):
if event == 'return':
f_locals.update(frame.f_locals)
return probe
sys.settrace(probe)
try: res = f(*args,**kwds)
finally: sys.settrace(None)
return (res, f_locals)
return wrapper
# example
@withlocals
def foo(x, y=0, *args, **kwds):
a = max(x,y)
b = len(args)
c = min(kwds.values())
return a+b+c
r,locs = foo(1,2,3,4,a=5,b=6)
print locs
George
More information about the Python-list
mailing list