parameters to lambda's executed at run time.

[Boris Borcic]

One way :

 >>> from functools import partial
 >>> def func(item) : print item

 >>> llist = [partial(func,item) for item in range(5)]
 >>> for thing in llist : thing()

0
1
2
3
4


wyleu wrote:
> I'm trying to supply parameters to a function that is called at a
> later time as in the code below:
> 
> llist = []
> 
> for item in range(5):
>     llist.append(lambda: func(item))
> 
> def func(item):
>     print item
> 
> for thing in llist:
>     thing()
> 
> which produces the result
> 
> IDLE 1.2.1
>>>> ================================ RESTART ================================
>>>>
> <function <lambda> at 0xb716356c>
> <function <lambda> at 0xb71635a4>
> <function <lambda> at 0xb71635dc>
> <function <lambda> at 0xb7163614>
> <function <lambda> at 0xb716364c>
>>>> ================================ RESTART ================================
>>>>
> 4
> 4
> 4
> 4
> 4
> 
> How can one allocate a different parameter to each instance of the
> function rather than all of them getting the final value of the loop?
>