?

[afrobeard]

The following proposed solution is not intended to be a solution, it
goes completely against the zen of python. [Type import this into the
python command interpreter]

I brought it down to two lines:-

l = range(6)
[1 if b!=4 else l.__delslice__(0,len(l)) for b in l][:-1]

itertools would still be a better approach in my opinion.

Just because I'm curious to know, can anyone bring it shorter[even if
its cryptic] than this without invoking any Python Library.

P.S. Once again I would not recommend using this as Explicit is better
than Implicit
P.P.S. It is strongly undesirable for us humans to use anything
starting with __ :)


On May 15, 5:10 pm, "Geoffrey Clements"
<geoffrey.clement... at SPAMbaesystems.com> wrote:
> "urikaluzhny" <ukaluz... at nds.com> wrote in message
>
> news:51e0f25d-474a-450a-ad00-92f70c893c6c at m44g2000hsc.googlegroups.com...
> On May 15, 10:06 am, "Terry Reedy" <tjre... at udel.edu> wrote:
>
> > "urikaluzhny" <ukaluz... at nds.com> wrote in message
>
> >news:f8229614-a000-450e-85eb-825e6c1386cf at w7g2000hsa.googlegroups.com...
> > | It seems that I rather frequently need a list or iterator of the form
> > | [x for x in <> while <>]
>
> > I can think of two ways to interpret that.
> >> I mean like [x for x in <A> if <B>], only that it breaks the loop when
> >> the expression <B> is false.
>
> def gen(a):
>     for x in a:
>         if B: break
>         yield x
>
> a_gen = gen(A)
>
> # now iterate over a_gen
>
> --
> Geoff