Responding to web request with python

scott212 busitones at gmail.com
Sat Nov 1 16:46:21 CET 2008


I'm responding with xml to a web request from google checkout but I
think I'm in a catch-22. To get my webserver (apache) to respond I
need a header and then a blank line before my xml begins, or else it
throws the 500 error. If have the blank line before the xml, the
service I'm responding to cannot parse it. If it's a response, can I
still use urllib or something like that? Is that my answer?

Thanks for all your help!



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