Why does numpy.array(a,b) have this meaning?
aleksandr.goretoy at gmail.com
Mon Nov 3 08:40:49 CET 2008
just a shot in the dark.
second arg to numpy.array is of type
On Mon, Nov 3, 2008 at 1:26 AM, Rick Giuly <rgiuly.group at yahoo.com> wrote:
> Hello All,
> Case 1
> This generates an error, which makes sense because the argument should
> be a list of numbers:
> Case 2
> This does not generate an error and the result is an array with a
> single element:
> a = numpy.array()
> b = numpy.array()
> The only different I see here between the numpy.array call in the
> cases is that
> a is a numpy int32
> 10 is an int
> Why would this minor difference in integer types cause a totally
> different result for the two cases - or is something else causing the
> difference in results?
> I am aware that numpy.array([10,10]) will work, but I'm trying to
> understand what is going on syntactically/semantically in the two
> cases above.
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