Python 3.0 - is this true?
duncan.booth at invalid.invalid
Sun Nov 9 15:40:22 CET 2008
Roy Smith wrote:
> In 3.0, can you still order types? In 2.x, you can do:
>>>> t1 = type(1)
>>>> t2 = type(1j)
>>>> t1 < t2
> If this still works in 3.0, then you can easily do something like:
> def total_order(o1, o2):
> "Compare any two objects of arbitrary types"
> return o1 <= o2
> except UncomparableTypesError: # whatever the right name is
> return type(o1) <= type(o2)
> and get the same effect as you had in 2.x.
No, that won't work. You can compare types for equality/inequality, but
they are not orderable:
>>> sorted([1, 'a'], key=lambda x:(type(x),x))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: type() < type()
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