Python IF THEN chain equivalence

jzakiya jzakiya at mail.com
Thu Nov 13 23:31:45 CET 2008


On Nov 13, 5:21 pm, Alan Baljeu <alanbal... at yahoo.com> wrote:
> I think you should rethink your post. The first case you posted makes no sense in any language I know.  Also, a whole lot of nested IF's is a bad idea in any language.  In Python, you will end up with code indented 40+ characters if you keep going.
>
> ----- Original Message ----
> From: jzakiya <jzak... at mail.com>
> To: python-l... at python.org
> Sent: Thursday, November 13, 2008 5:06:53 PM
> Subject: Python IF THEN chain equivalence
>
> I'm translating a program in Python that has this IF Then chain
>
> IF  x1 < limit:   --- do a ---
>     IF  x2 < limit:  --- do b ---
>         IF x3 < limit:  --- do c ---
>                        .-----
>                         ------
>                     IF  x10 < limt: --- do j ---
>                     THEN
>                  THEN
>               -----
>           THEN
>      THEN
> THEN
>
> In other words, as long as    'xi' is less than 'limit' keep going
> down the chain, and when 'xi' isn't less than 'limit' jump to end of
> chain a continue.
>
> Is this the equivalence in Python?
>
> IF  x1 < limit:
>         --- do a  ---
> elif x2 < limit:
>         --- do b ---
> ----
> ----
> elif x10 < limit:
>        --- do j ---
>
> --http://mail.python.org/mailman/listinfo/python-list
>
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>
>

In the code the 'xi's and 'limit' are variables and the --- do letters
---
phrases are simply writes to any array:   an_array[xi]=0

Actually, the code makes perfectly good sense, and is a necessity of
the algorithm I'm implementing, and works perfectly good in Forth, and
can be
written quite nicely within a normal page width.

I was just hoping I could perform the equivalent chain in Python
without
having to grossly indent the source code past the normal width of a
printed page.
But if that's the only way to do it in Python, then so be it.



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