Sort dictionary by value when value is a list
major-john
iamh2o at gmail.com
Fri Nov 14 13:26:45 EST 2008
I'm having trouble sorting a dictionary based on values when the values are
all lists, and i want to sort the list by key with the largest value lists
in decreasing size.
Currently, I have the following:
from operator import itemgetter
dict = {'A': [(10, 20), (12, 18), (5, 11), (18, 25)], 'C': [(1, 200)], 'B':
[(1, 10), (100, 200), (150, 300), (250, 350), (300, 400)], 'D': [(3, 400)]}
I have tried several methods, and seem to have come closest using:
sorted(self.dict.items(), key=itemgetter(1), reverse=True)
My problem is that this will return the key order A,D,C,B
The order I want is based on the size of the lists each key points to:
B,A,D,C or B,A,C,D
Question:
itemgetter(1) is just returning the value, which is a list. How do I
specify that I want the values to be sorted by list size?
Thanks!
john
--
"We are healthy only to the extent that our ideas are humane." --Killgore
Trout
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