a regual expression problem

[Roy Smith]

In article 
<8cb784fc-809b-444e-b8a7-e4129a4a58ee at w24g2000prd.googlegroups.com>,
 lookon <areyoulookon at gmail.com> wrote:

> I have a url of image, and I want to get the filename and extension of
> the image. How to write in python?
> 
> for example, the url is http://a.b.com/aaa.jpg?version=1.1
> 
> how can I get aaa and jpg by python?

Despite the subject line, this is *not* a regex problem.  The right tool is 
Python's built-in urlparse module, which understands the full syntax of 
urls.  Trying to roll your own from scratch using split() or regex is the 
wrong solution.