# question regarding list comprehensions

Pat Pat at junk.com
Mon Oct 20 18:49:10 CEST 2008

```Steven D'Aprano wrote:
> On Mon, 20 Oct 2008 10:20:03 -0400, Pat wrote:
>
>> Finally, if someone could point me to a good tutorial or explain list
>> compressions I would be forever in your debt.
>
> Think of a for-loop:
>
> for x in (1, 2, 3):
>     x
>
> Creates x=1, then x=2, then x=3. It doesn't do anything with the x's, but
> just creates them. Let's turn it into a list comp, and collect the x's:
>
>>>> [x for x in (1, 2, 3)]
> [1, 2, 3]
>
>
>
> for x in (1, 2, 3):
>     2*x+1
>
> Creates x=1, then evaluates 2*x+1 = 3. Then it repeats for x=2, then x=3.
> Here it is as a list comp:
>
>>>> [2*x+1 for x in (1, 2, 3)]
> [3, 5, 7]
>
>
>
> for x in (1, 2, 3):
>     if x != 2:
>         2*x+1
>
> Here it is as a list comp:
>
>>>> [2*x+1 for x in (1, 2, 3) if x != 2]
> [3, 7]
>
>
> You can use any sort of sequence inside a list comp, not just a tuple.
>
>>>> [c.upper() for c in "abcd"]
> ['A', 'B', 'C', 'D']
>
>
> You can nest list comps:
>
>>>> [y+1 for y in [2*x+1 for x in (1, 2, 3)]]
> [4, 6, 8]
>
>
> Advanced: you can use tuple-unpacking:
>
>>>> [(y,x) for (x,y) in [(1,2), (3, 4)]]
> [(2, 1), (4, 3)]
>
> and also multiple for-loops:
>
>>>> [(x,c) for x in (1, 2) for c in "abc"]
> [(1, 'a'), (1, 'b'), (1, 'c'), (2, 'a'), (2, 'b'), (2, 'c')]
>
>
>
> That last one is close to:
>
> for x in (1, 2):
>     for c in "abc":
>         (x, c)
>
>

Thank you.  I think that clears up the mystery a bit.  I added your note
to my snippets file. When I have a situation that I can't resolve, I'll