default value in __init__

[Lawrence D'Oliveiro]

In message <Xns9B33BC4CC1480duncanbooth at 127.0.0.1>, Duncan Booth wrote:

> We already get people asking why code like this doesn't return 3:
> 
>>>> fns = [ lambda: x for x in range(10) ]
>>>> fns[3]()
> 9
> 
> ... making this change to default arguments would mean the
> solution usually proposed to the function scoping question above would no
> longer work:
> 
>>>> fns = [ lambda y=x: y for x in range(10) ]
>>>> fns[3]()
> 3

The right solution, of course, is

    fns = [(lambda x : lambda : x)(x) for x in range(10)]