how to get the thighest bit position in big integers?
Rich Healey
healey.rich at gmail.com
Sun Oct 5 20:02:30 EDT 2008
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Aaron "Castironpi" Brady wrote:
> Duncan Booth wrote:
>> mmgarvey at gmx.de wrote:
>>
>>> My question to the group: Does anyone know of a non-hackish way to
>>> determine the required bit position in python? I know that my two
>>> ideas
>>> can be combined to get something working. But is there a *better* way,
>>> that isn't that hackish?
>>>
>> How about using the hex representation of the value?
>>
>> OFFSET = dict(("%x"%i, int(c)) for i,c in enumerate("5433222211111111"))
>> def get_highest_bit_num(r):
>> s = "%x"%r
>> return len(s) * 4 - OFFSET[s[0]]
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>
> You can replace the dict if it's faster.
>
> OFFSET= tuple( int(x) for x in "5433222211111111" )
> def get_highest_bit_num(r):
> s = "%x"%r
> return len(s) * 4 - OFFSET[int(s[0],16)]
>
> P.S. Back home, this sort of 'nitpicking' would be judged
> unconstructive. Worth pointing out, or not worth saying?
>
> P.S.S. 'Thighest' bit? I thought the spam filters would catch that.
>
That should be P.P.S.
PS: This is also unconstructive nitpicking.
Kind regards
Rich ;)
- --
Rich Healey - iTReign \ .''`. / healey.rich at gmail.com
Developer / Systems Admin \ : :' : / healey.rich at itreign.com
AIM: richohealey33 \ `. `' / richo at psych0tik.net
MSN: bitchohealey at hotmail.com \ `- / richohealey at hellboundhackers.org
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