Do I need a lock here?
Diez B. Roggisch
deets at nospam.web.de
Mon Oct 27 05:12:33 EDT 2008
jasiu85 schrieb:
> Hey,
>
> Please take a look at the code of the two threads below:
>
> COMMON_DICT = {}
>
> def thread_1():
> global COMMON_DICT
> local_dict = prepare_dict()
> COMMON_DICT = local_dict
>
> def thread_2():
> global COMMON_DICT
> local_dict = COMMON_DICT
> use_dict(local_dict)
>
> Do I need a lock to protect the COMMON_DICT dictionary? AFAIK bytecode
> operations are atomic and in each thread there's only one crucial
> bytecode op: STORE_NAME in the first thread and LOAD_NAME in the
> second one. So I suspect that everything will work just fine. Am I
> right?
Depending on what you mean by "right".
The above is not enough to judge what is really happening. But depending
on the execution order, thread_1 overwrites the reference in COMMON_DICT
*after* thread_2 has altered it.
But it won't crash or anything. If that's right for you.
Diez
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