Sorting a list

[Steve Holden]

RC wrote:
> unsortedList = list(["XYZ","ABC"])
> 
> sortedList = unsortedList.sort()
> print sortedList
> 
> 
> Why this return None?
> How do I get return as ["ABC", "XYZ"]?

The list's .sort method returns None because it modifies the list
in-place, so after the call it is sorted. So you can either not assign
the list and use unsortedList (whose name now belies its sorted
condition) or you can use

sprtedList = sorted(unsortedList)

since the sorted() function returns a sorted copy of its argument.

regards
 Steve
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