Sorting a list

[Brian Blais]

On Oct 28, 2008, at 9:45 , RC wrote:

> unsortedList = list(["XYZ","ABC"])
>
> sortedList = unsortedList.sort()
> print sortedList
>

the sort method is in-place, so it modifies the object which calls  
it, and doesn't return anything:

In [1]:unsortedList = list(["XYZ","ABC"])

In [2]:sortedList = unsortedList.sort()

In [3]:print sortedList
None

In [4]:print unsortedList
['ABC', 'XYZ']

or, better, just:

In [5]:unsortedList = list(["XYZ","ABC"])

In [6]:unsortedList.sort()

In [7]:print unsortedList
['ABC', 'XYZ']


						bb

-- 
Brian Blais
bblais at bryant.edu
http://web.bryant.edu/~bblais



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