bfrederi wrote: >> > image.crop((x1,y1,x2,y2)) >> >> This doesn't change `image` but creates and returns a new cropped image >> which you simply ignore. >> >> > image.save(file_name, "JPEG") >> >> Ciao, >> Marc 'BlackJack' Rintsch > > How do I output it to an actual file then? Or overwrite the existing > file? cropped_image = image.crop(...) cropped_image.save(...) Peter